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Lexicographic Increasing Order

Lexicographic increasing order refers to arranging elements or objects in ascending order based on their lexicographic order. In lexicographic order, elements are compared character by character, and the order is determined by the alphabetical or numerical value of each character. For example, consider a list of strings: ["apple", "banana", "cherry", "apricot"]. When arranged in lexicographic increasing order, the list would be ["apricot", "apple", "banana", "cherry"]. The comparison starts with the first character of each string, and if the characters are equal, the comparison moves to the next character. In this case, "apricot" comes before "apple" because 'p' comes before 'p' and 'r' comes before 'p'. Similarly, "apple" comes before "banana" because 'a' comes before 'b'. The concept of lexicographic increasing order

Java program to take two string as command line arguments and check that they are equal or not.

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  /* Do not use '==' operator for comparing strings in java.  Because '==' checks if both objects point to the same memory address or location  and .equals() compares values in the objects. This program is made using library functions and without using library functions. Here in this program I am using string library functions .equals() and .equalsIgnoreCase() which gives output as boolean values true or false. */ import java.util.*; public class str_cmp_cmd_line {      public static void main(String[] args)      {      System.out.println("First Input String ="+args[0]);       //Commmand line arguments always starts from 0 i.e. args[0]       System.out.println("Second Input String ="+args[1]);      System.out.println("By using string library function of equals()");      System.out.println("Input string1= "+args[0]+" & string2= "+args[1]+" are equal :"+args[0].equals(args[1]));      // Here equals() check

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Lexicographic Increasing Order

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